zaneb131
zaneb131
03-06-2018
Mathematics
contestada
Find the angles please please
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adrielcavalcant
adrielcavalcant
03-06-2018
Angle BAC
cosφ⁻¹ = (10² + 17² - 11²)/(2*10*17) = 37.9 ≈ 38°
Angle ACB
cosφ⁻¹ = (10² + 11² - 17²)/(2*10*11) = 108.0°
Angle ABC
cosφ⁻¹ = (11² + 17² - 10²)/(2*11*17) = 34.0°
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