Respuesta :
Answer:
Explanation:
3S + 2Al = Al₂S₃
3 x 26.98 2 x 26.98
96.18gm 53.96 gm
sulfur is in short supply so sulphur will be the limiting reagent
4.8 gm sulphur will require 53.96 x 4.8 / 96.18 gm of Al
53.96 x 4.8 / 96.18 gm
= 2.69 gm
aluminium sulphide formed
= 4.8 + 2.69
= 7.49 gm
percentage of yield = 4.5 x100 / 7.49
= 60 %
The study of chemicals and bonds is called chemistry.
[tex]3S + 2Al = Al_2S_3[/tex]
The molecular mass of the compound Fe and Al is as follows
- [tex]3 * 26.98[/tex] = 96.18gm
- [tex]2 * 26.98[/tex] = 53.96 gm
The sulphur is the limiting reagent that decides the rate of production of the compound.
Hence, the 4.8 gm sulphur will require as follows:-
[tex]\frac{53.96 * 4.8 }{ 96.18}[/tex] = 2.69 gm
The aluminium sulphide formed is:-
[tex]= 4.8 + 2.69[/tex] = 7.49 gm
The percentage of yield is as follows:-
[tex]\frac{4.5 *100}{7.49}[/tex]
= 60 %
Hence, the correct answer is 60%.
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