Respuesta :

Harshiiiii

Answer:

if you don't understand please find the attachment

Step-by-step explanation:

We have, y=x ^x

Taking log on both the sides, we get

logy=xlogx

On differentiating w.r.t. x, we get

=

x

x

+logx

⇒

dx

dy

=y+ylogx

⇒

dx

dy

=x x

(1+logx) ....(∵y=x ^x )

Ver imagen Harshiiiii

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