VishvC764716
VishvC764716
03-11-2022
Mathematics
contestada
2) f(n) = 10.2^n at n=5
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SherD290999
SherD290999
03-11-2022
F(n) = 10 . 2^n
To calculate F(5) , replace n by 5, and solve:
F(5)= 10 . 2^5 = 10 . 32 = 320
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