Respuesta :

[tex]\begin{gathered} \frac{19}{5x^3y^2}-\frac{1}{5xy} \\ \\ \frac{19(5xy)-5x^3y^2}{(5x^3y^2)\cdot(5xy)} \\ \\ \frac{95xy-5x^3y^2}{25x^4y^3} \\ \\ \frac{5xy(19-x^2y)}{5xy(5x^3y^2)} \\ \\ \frac{19-x^2y}{5x^3y^2} \\ \\ \text{The simplification of }\frac{19}{5x^3y^2}-\frac{1}{5xy}\text{ is }\frac{19-x^2y}{5x^3y^2} \end{gathered}[/tex]

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