X^2+(y-5)=25 find the center of the circle

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03-01-2018
Mathematics

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X^2+(y-5)=25 find the center of the circle

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mathildaramaqap1ywpc mathildaramaqap1ywpc · Answer 1 · 2018-01-03T08:28:40+01:00

mathildaramaqap1ywpc mathildaramaqap1ywpc

03-01-2018

[tex] {x}^{2} + (y - 5) = 25 \\ {x }^{2} + y = 25 + 5 \\ {x}^{2} + y = 30 \\ {x}^{2} + y = \sqrt{30} \\ [/tex]
centre: (0,0)
Radius: square root of 30

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