Gracie723
Gracie723
03-04-2018
Mathematics
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(2a+b)^2÷(3b-1) when a= -2 and b=5
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zrh2sfo
zrh2sfo
03-04-2018
Evaluate (2 a + b)^2/(3 b - 1) where a = -2 and b = 5:
(2 a + b)^2/(3 b - 1) = (5 - 2×2)^2/(3×5 - 1)
3×5 = 15:
(5 - 2×2)^2/(15 - 1)
| 1 | 5
- | | 1
| 1 | 4:
(5 - 2×2)^2/14
2 (-2) = -4:
(-4 + 5)^2/14
5 - 4 = 1:
1^2/14
1^2 = 1:
Answer: 1/14
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