dhoshika dhoshika
  • 04-04-2018
  • Mathematics
contestada

root 8 + 3 root 32 - root 50

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Аноним Аноним
  • 04-04-2018
[tex] \sqrt{8} + 3 \sqrt{32} - \sqrt{50} [/tex]

[tex] = \sqrt{4 \times 2} + 3 \sqrt{16 \times 2} - \sqrt{25 \times 2} [/tex]

[tex] = 2\sqrt{ 2} + 12 \sqrt{2} - 5\sqrt{ 2} [/tex]

[tex]= 9\sqrt{ 2} [/tex]
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