dabmcnugget6976 dabmcnugget6976
  • 02-05-2018
  • Physics
contestada

Where must an object be placed to form an image 30.0 cm from a diverging lens with a focal length of 43.0 cm?

Respuesta :

jushmk
jushmk jushmk
  • 12-05-2018
Using lens equation;

1/o + 1/i = 1/f; where o = Object distance, i = image distance (normally negative), f = focal length (normally negative)

Substituting;

1/o + 1/-30 = 1/-43 => 1/o = -1/43 + 1/30 = 0.01 => o = 1/0.01 = 99.23 cm

Therefore, the object should be place 99.23 cm from the lens.
Answer Link

Otras preguntas

3-2i/5i+2 What is the solution?
the cards in a card catalog are filed in what manner? A: by publication B: by subject C: alphabetically D: by call number
briefly describe Theodore Geisel's career in advertising
A bottle of fruit juice is 800 milliliters. How many liters of fruit juice are in 120 bottles?
Are many valuable minerals found in or near areas of volcanic activity and mountain building?
An illegal drug stimulates the parasympathetic nervous system, causing the user to appear tranquilized. What could indicate to a paramedic whether or not the pe
HELP HELP HELP HELP PLEASE (sorry ) can u complete this tiny is to .................. as broad is to ........................ the words to fill this in are tiny
What is .5v^1/3 Can u please help? Ian super lost!!!!!!
why did farmers follow railroads into the texas frontier
which is an example of an intentional injury