abigailbarnes8242 abigailbarnes8242
  • 04-02-2021
  • Mathematics
contestada

Solve the equation for x:
sin^2 x – 2 cos x - 2 = 0
for the restriction 0 < x < 2pi

Solve the equation for x sin2 x 2 cos x 2 0 for the restriction 0 lt x lt 2pi class=

Respuesta :

Аноним Аноним
  • 04-02-2021

Answer: x = pi

sin²x - 2cos x - 2 = 0

⇔ 1 - cos²x - 2cos x - 2 = 0

⇔ cos²x + 2cos x + 1 = 0

⇔ (cos x + 1)² = 0

⇒ cos x + 1 = 0

⇔ cos x = -1

⇒ x = pi + k2pi

because 0 ≤ x < 2pi

=> x = pi

Step-by-step explanation:

Answer Link

Otras preguntas

The French lost the 7 Years War to which country? 7
In a speech Mario's voice is flat and unchanging, which makes his delivery boring. Which quality makes of Mario's speech needs most improvement? A. Gestures B.
Selena buys 4 peaches that weigh 1 pound in all. Each peach weighs the same amount. Peaches are on sale for $2.24 per pound.
Examine this system of equations. Which numbers can be multiplied by each equation so that when the two equations are added together, the y term is eliminated?
French hw plz do it :)
what is the value of n
True or False: Because Italy was made up of hundreds of small independent states competing for resources, war and conquering was a normal part of Roman culture
In this problem, substitute (x+1) in place of y in the second equation.​
What fraction of 1/2 is 1/3??
Next week is tinas ninth birthday, and her parents have promised her a special time. Tina wonders if they are planning to give her a surprise party. She is find